Integrand size = 21, antiderivative size = 202 \[ \int \frac {a+b \tan (c+d x)}{\cot ^{\frac {5}{2}}(c+d x)} \, dx=-\frac {(a-b) \arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2} d}+\frac {(a-b) \arctan \left (1+\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2} d}+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}+\frac {2 a}{3 d \cot ^{\frac {3}{2}}(c+d x)}-\frac {2 b}{d \sqrt {\cot (c+d x)}}-\frac {(a+b) \log \left (1-\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )}{2 \sqrt {2} d}+\frac {(a+b) \log \left (1+\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )}{2 \sqrt {2} d} \]
2/5*b/d/cot(d*x+c)^(5/2)+2/3*a/d/cot(d*x+c)^(3/2)+1/2*(a-b)*arctan(-1+2^(1 /2)*cot(d*x+c)^(1/2))/d*2^(1/2)+1/2*(a-b)*arctan(1+2^(1/2)*cot(d*x+c)^(1/2 ))/d*2^(1/2)-1/4*(a+b)*ln(1+cot(d*x+c)-2^(1/2)*cot(d*x+c)^(1/2))/d*2^(1/2) +1/4*(a+b)*ln(1+cot(d*x+c)+2^(1/2)*cot(d*x+c)^(1/2))/d*2^(1/2)-2*b/d/cot(d *x+c)^(1/2)
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.91 (sec) , antiderivative size = 207, normalized size of antiderivative = 1.02 \[ \int \frac {a+b \tan (c+d x)}{\cot ^{\frac {5}{2}}(c+d x)} \, dx=\frac {\sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)} \left (-40 a \left (-1+\operatorname {Hypergeometric2F1}\left (\frac {3}{4},1,\frac {7}{4},-\tan ^2(c+d x)\right )\right ) \tan ^{\frac {3}{2}}(c+d x)+3 b \left (-10 \sqrt {2} \arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )+10 \sqrt {2} \arctan \left (1+\sqrt {2} \sqrt {\tan (c+d x)}\right )-5 \sqrt {2} \log \left (1-\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )+5 \sqrt {2} \log \left (1+\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )-40 \sqrt {\tan (c+d x)}+8 \tan ^{\frac {5}{2}}(c+d x)\right )\right )}{60 d} \]
(Sqrt[Cot[c + d*x]]*Sqrt[Tan[c + d*x]]*(-40*a*(-1 + Hypergeometric2F1[3/4, 1, 7/4, -Tan[c + d*x]^2])*Tan[c + d*x]^(3/2) + 3*b*(-10*Sqrt[2]*ArcTan[1 - Sqrt[2]*Sqrt[Tan[c + d*x]]] + 10*Sqrt[2]*ArcTan[1 + Sqrt[2]*Sqrt[Tan[c + d*x]]] - 5*Sqrt[2]*Log[1 - Sqrt[2]*Sqrt[Tan[c + d*x]] + Tan[c + d*x]] + 5 *Sqrt[2]*Log[1 + Sqrt[2]*Sqrt[Tan[c + d*x]] + Tan[c + d*x]] - 40*Sqrt[Tan[ c + d*x]] + 8*Tan[c + d*x]^(5/2))))/(60*d)
Time = 0.73 (sec) , antiderivative size = 198, normalized size of antiderivative = 0.98, number of steps used = 21, number of rules used = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.952, Rules used = {3042, 4156, 3042, 4012, 3042, 4012, 25, 3042, 4012, 3042, 4017, 25, 1482, 1476, 1082, 217, 1479, 25, 27, 1103}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {a+b \tan (c+d x)}{\cot ^{\frac {5}{2}}(c+d x)} \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \frac {a+b \tan (c+d x)}{\cot (c+d x)^{5/2}}dx\) |
\(\Big \downarrow \) 4156 |
\(\displaystyle \int \frac {a \cot (c+d x)+b}{\cot ^{\frac {7}{2}}(c+d x)}dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \frac {b-a \tan \left (c+d x+\frac {\pi }{2}\right )}{\left (-\tan \left (c+d x+\frac {\pi }{2}\right )\right )^{7/2}}dx\) |
\(\Big \downarrow \) 4012 |
\(\displaystyle \int \frac {a-b \cot (c+d x)}{\cot ^{\frac {5}{2}}(c+d x)}dx+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \frac {a+b \tan \left (c+d x+\frac {\pi }{2}\right )}{\left (-\tan \left (c+d x+\frac {\pi }{2}\right )\right )^{5/2}}dx+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}\) |
\(\Big \downarrow \) 4012 |
\(\displaystyle \int -\frac {b+a \cot (c+d x)}{\cot ^{\frac {3}{2}}(c+d x)}dx+\frac {2 a}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle -\int \frac {b+a \cot (c+d x)}{\cot ^{\frac {3}{2}}(c+d x)}dx+\frac {2 a}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\int \frac {b-a \tan \left (c+d x+\frac {\pi }{2}\right )}{\left (-\tan \left (c+d x+\frac {\pi }{2}\right )\right )^{3/2}}dx+\frac {2 a}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}\) |
\(\Big \downarrow \) 4012 |
\(\displaystyle -\int \frac {a-b \cot (c+d x)}{\sqrt {\cot (c+d x)}}dx+\frac {2 a}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}-\frac {2 b}{d \sqrt {\cot (c+d x)}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\int \frac {a+b \tan \left (c+d x+\frac {\pi }{2}\right )}{\sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )}}dx+\frac {2 a}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}-\frac {2 b}{d \sqrt {\cot (c+d x)}}\) |
\(\Big \downarrow \) 4017 |
\(\displaystyle -\frac {2 \int -\frac {a-b \cot (c+d x)}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}}{d}+\frac {2 a}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}-\frac {2 b}{d \sqrt {\cot (c+d x)}}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {2 \int \frac {a-b \cot (c+d x)}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}}{d}+\frac {2 a}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}-\frac {2 b}{d \sqrt {\cot (c+d x)}}\) |
\(\Big \downarrow \) 1482 |
\(\displaystyle -\frac {2 \left (-\frac {1}{2} (a+b) \int \frac {1-\cot (c+d x)}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}-\frac {1}{2} (a-b) \int \frac {\cot (c+d x)+1}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}\right )}{d}+\frac {2 a}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}-\frac {2 b}{d \sqrt {\cot (c+d x)}}\) |
\(\Big \downarrow \) 1476 |
\(\displaystyle -\frac {2 \left (-\frac {1}{2} (a+b) \int \frac {1-\cot (c+d x)}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}-\frac {1}{2} (a-b) \left (\frac {1}{2} \int \frac {1}{\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}+\frac {1}{2} \int \frac {1}{\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}\right )\right )}{d}+\frac {2 a}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}-\frac {2 b}{d \sqrt {\cot (c+d x)}}\) |
\(\Big \downarrow \) 1082 |
\(\displaystyle -\frac {2 \left (-\frac {1}{2} (a+b) \int \frac {1-\cot (c+d x)}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}-\frac {1}{2} (a-b) \left (\frac {\int \frac {1}{-\cot (c+d x)-1}d\left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}-\frac {\int \frac {1}{-\cot (c+d x)-1}d\left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}\right )\right )}{d}+\frac {2 a}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}-\frac {2 b}{d \sqrt {\cot (c+d x)}}\) |
\(\Big \downarrow \) 217 |
\(\displaystyle -\frac {2 \left (-\frac {1}{2} (a+b) \int \frac {1-\cot (c+d x)}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}-\frac {1}{2} (a-b) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )\right )}{d}+\frac {2 a}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}-\frac {2 b}{d \sqrt {\cot (c+d x)}}\) |
\(\Big \downarrow \) 1479 |
\(\displaystyle -\frac {2 \left (-\frac {1}{2} (a+b) \left (-\frac {\int -\frac {\sqrt {2}-2 \sqrt {\cot (c+d x)}}{\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}}{2 \sqrt {2}}-\frac {\int -\frac {\sqrt {2} \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}}{2 \sqrt {2}}\right )-\frac {1}{2} (a-b) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )\right )}{d}+\frac {2 a}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}-\frac {2 b}{d \sqrt {\cot (c+d x)}}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle -\frac {2 \left (-\frac {1}{2} (a+b) \left (\frac {\int \frac {\sqrt {2}-2 \sqrt {\cot (c+d x)}}{\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}}{2 \sqrt {2}}+\frac {\int \frac {\sqrt {2} \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}}{2 \sqrt {2}}\right )-\frac {1}{2} (a-b) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )\right )}{d}+\frac {2 a}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}-\frac {2 b}{d \sqrt {\cot (c+d x)}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle -\frac {2 \left (-\frac {1}{2} (a+b) \left (\frac {\int \frac {\sqrt {2}-2 \sqrt {\cot (c+d x)}}{\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}}{2 \sqrt {2}}+\frac {1}{2} \int \frac {\sqrt {2} \sqrt {\cot (c+d x)}+1}{\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}\right )-\frac {1}{2} (a-b) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )\right )}{d}+\frac {2 a}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}-\frac {2 b}{d \sqrt {\cot (c+d x)}}\) |
\(\Big \downarrow \) 1103 |
\(\displaystyle -\frac {2 \left (-\frac {1}{2} (a-b) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )-\frac {1}{2} (a+b) \left (\frac {\log \left (\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{2 \sqrt {2}}\right )\right )}{d}+\frac {2 a}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {2 b}{5 d \cot ^{\frac {5}{2}}(c+d x)}-\frac {2 b}{d \sqrt {\cot (c+d x)}}\) |
(2*b)/(5*d*Cot[c + d*x]^(5/2)) + (2*a)/(3*d*Cot[c + d*x]^(3/2)) - (2*b)/(d *Sqrt[Cot[c + d*x]]) - (2*(-1/2*((a - b)*(-(ArcTan[1 - Sqrt[2]*Sqrt[Cot[c + d*x]]]/Sqrt[2]) + ArcTan[1 + Sqrt[2]*Sqrt[Cot[c + d*x]]]/Sqrt[2])) - ((a + b)*(-1/2*Log[1 - Sqrt[2]*Sqrt[Cot[c + d*x]] + Cot[c + d*x]]/Sqrt[2] + L og[1 + Sqrt[2]*Sqrt[Cot[c + d*x]] + Cot[c + d*x]]/(2*Sqrt[2])))/2))/d
3.9.4.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( -1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & & (LtQ[a, 0] || LtQ[b, 0])
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S implify[a*(c/b^2)]}, Simp[-2/b Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b )], x] /; RationalQ[q] && (EqQ[q^2, 1] || !RationalQ[b^2 - 4*a*c])] /; Fre eQ[{a, b, c}, x]
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 2*(d/e), 2]}, Simp[e/(2*c) Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ e/(2*c) Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ -2*(d/e), 2]}, Simp[e/(2*c*q) Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Simp[e/(2*c*q) Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ a*c, 2]}, Simp[(d*q + a*e)/(2*a*c) Int[(q + c*x^2)/(a + c*x^4), x], x] + Simp[(d*q - a*e)/(2*a*c) Int[(q - c*x^2)/(a + c*x^4), x], x]] /; FreeQ[{a , c, d, e}, x] && NeQ[c*d^2 + a*e^2, 0] && NeQ[c*d^2 - a*e^2, 0] && NegQ[(- a)*c]
Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(b*c - a*d)*((a + b*Tan[e + f*x])^(m + 1)/ (f*(m + 1)*(a^2 + b^2))), x] + Simp[1/(a^2 + b^2) Int[(a + b*Tan[e + f*x] )^(m + 1)*Simp[a*c + b*d - (b*c - a*d)*Tan[e + f*x], x], x], x] /; FreeQ[{a , b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && LtQ[m, -1 ]
Int[((c_) + (d_.)*tan[(e_.) + (f_.)*(x_)])/Sqrt[(b_.)*tan[(e_.) + (f_.)*(x_ )]], x_Symbol] :> Simp[2/f Subst[Int[(b*c + d*x^2)/(b^2 + x^4), x], x, Sq rt[b*Tan[e + f*x]]], x] /; FreeQ[{b, c, d, e, f}, x] && NeQ[c^2 - d^2, 0] & & NeQ[c^2 + d^2, 0]
Int[(cot[(e_.) + (f_.)*(x_)]*(d_.))^(m_)*((a_) + (b_.)*tan[(e_.) + (f_.)*(x _)]^(n_.))^(p_.), x_Symbol] :> Simp[d^(n*p) Int[(d*Cot[e + f*x])^(m - n*p )*(b + a*Cot[e + f*x]^n)^p, x], x] /; FreeQ[{a, b, d, e, f, m, n, p}, x] && !IntegerQ[m] && IntegersQ[n, p]
Time = 1.10 (sec) , antiderivative size = 248, normalized size of antiderivative = 1.23
method | result | size |
derivativedivides | \(-\frac {-24 b \left (\tan ^{\frac {5}{2}}\left (d x +c \right )\right )-40 a \left (\tan ^{\frac {3}{2}}\left (d x +c \right )\right )+15 a \sqrt {2}\, \ln \left (-\frac {\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )-\tan \left (d x +c \right )-1}{1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )-15 b \sqrt {2}\, \ln \left (-\frac {1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )-\tan \left (d x +c \right )-1}\right )+30 a \sqrt {2}\, \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )-30 b \sqrt {2}\, \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+30 a \sqrt {2}\, \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )-30 b \sqrt {2}\, \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+120 b \left (\sqrt {\tan }\left (d x +c \right )\right )}{60 d \left (\frac {1}{\tan \left (d x +c \right )}\right )^{\frac {5}{2}} \tan \left (d x +c \right )^{\frac {5}{2}}}\) | \(248\) |
default | \(-\frac {-24 b \left (\tan ^{\frac {5}{2}}\left (d x +c \right )\right )-40 a \left (\tan ^{\frac {3}{2}}\left (d x +c \right )\right )+15 a \sqrt {2}\, \ln \left (-\frac {\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )-\tan \left (d x +c \right )-1}{1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )-15 b \sqrt {2}\, \ln \left (-\frac {1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )-\tan \left (d x +c \right )-1}\right )+30 a \sqrt {2}\, \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )-30 b \sqrt {2}\, \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+30 a \sqrt {2}\, \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )-30 b \sqrt {2}\, \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+120 b \left (\sqrt {\tan }\left (d x +c \right )\right )}{60 d \left (\frac {1}{\tan \left (d x +c \right )}\right )^{\frac {5}{2}} \tan \left (d x +c \right )^{\frac {5}{2}}}\) | \(248\) |
-1/60/d*(-24*b*tan(d*x+c)^(5/2)-40*a*tan(d*x+c)^(3/2)+15*a*2^(1/2)*ln(-(2^ (1/2)*tan(d*x+c)^(1/2)-tan(d*x+c)-1)/(1+2^(1/2)*tan(d*x+c)^(1/2)+tan(d*x+c )))-15*b*2^(1/2)*ln(-(1+2^(1/2)*tan(d*x+c)^(1/2)+tan(d*x+c))/(2^(1/2)*tan( d*x+c)^(1/2)-tan(d*x+c)-1))+30*a*2^(1/2)*arctan(1+2^(1/2)*tan(d*x+c)^(1/2) )-30*b*2^(1/2)*arctan(1+2^(1/2)*tan(d*x+c)^(1/2))+30*a*2^(1/2)*arctan(-1+2 ^(1/2)*tan(d*x+c)^(1/2))-30*b*2^(1/2)*arctan(-1+2^(1/2)*tan(d*x+c)^(1/2))+ 120*b*tan(d*x+c)^(1/2))/(1/tan(d*x+c))^(5/2)/tan(d*x+c)^(5/2)
Leaf count of result is larger than twice the leaf count of optimal. 616 vs. \(2 (164) = 328\).
Time = 0.27 (sec) , antiderivative size = 616, normalized size of antiderivative = 3.05 \[ \int \frac {a+b \tan (c+d x)}{\cot ^{\frac {5}{2}}(c+d x)} \, dx=\frac {15 \, d \sqrt {\frac {d^{2} \sqrt {-\frac {a^{4} - 2 \, a^{2} b^{2} + b^{4}}{d^{4}}} + 2 \, a b}{d^{2}}} \log \left ({\left (a d^{3} \sqrt {-\frac {a^{4} - 2 \, a^{2} b^{2} + b^{4}}{d^{4}}} - {\left (a^{2} b - b^{3}\right )} d\right )} \sqrt {\frac {d^{2} \sqrt {-\frac {a^{4} - 2 \, a^{2} b^{2} + b^{4}}{d^{4}}} + 2 \, a b}{d^{2}}} - {\left (a^{4} - b^{4}\right )} \sqrt {\tan \left (d x + c\right )}\right ) - 15 \, d \sqrt {\frac {d^{2} \sqrt {-\frac {a^{4} - 2 \, a^{2} b^{2} + b^{4}}{d^{4}}} + 2 \, a b}{d^{2}}} \log \left (-{\left (a d^{3} \sqrt {-\frac {a^{4} - 2 \, a^{2} b^{2} + b^{4}}{d^{4}}} - {\left (a^{2} b - b^{3}\right )} d\right )} \sqrt {\frac {d^{2} \sqrt {-\frac {a^{4} - 2 \, a^{2} b^{2} + b^{4}}{d^{4}}} + 2 \, a b}{d^{2}}} - {\left (a^{4} - b^{4}\right )} \sqrt {\tan \left (d x + c\right )}\right ) - 15 \, d \sqrt {-\frac {d^{2} \sqrt {-\frac {a^{4} - 2 \, a^{2} b^{2} + b^{4}}{d^{4}}} - 2 \, a b}{d^{2}}} \log \left ({\left (a d^{3} \sqrt {-\frac {a^{4} - 2 \, a^{2} b^{2} + b^{4}}{d^{4}}} + {\left (a^{2} b - b^{3}\right )} d\right )} \sqrt {-\frac {d^{2} \sqrt {-\frac {a^{4} - 2 \, a^{2} b^{2} + b^{4}}{d^{4}}} - 2 \, a b}{d^{2}}} - {\left (a^{4} - b^{4}\right )} \sqrt {\tan \left (d x + c\right )}\right ) + 15 \, d \sqrt {-\frac {d^{2} \sqrt {-\frac {a^{4} - 2 \, a^{2} b^{2} + b^{4}}{d^{4}}} - 2 \, a b}{d^{2}}} \log \left (-{\left (a d^{3} \sqrt {-\frac {a^{4} - 2 \, a^{2} b^{2} + b^{4}}{d^{4}}} + {\left (a^{2} b - b^{3}\right )} d\right )} \sqrt {-\frac {d^{2} \sqrt {-\frac {a^{4} - 2 \, a^{2} b^{2} + b^{4}}{d^{4}}} - 2 \, a b}{d^{2}}} - {\left (a^{4} - b^{4}\right )} \sqrt {\tan \left (d x + c\right )}\right ) + \frac {4 \, {\left (3 \, b \tan \left (d x + c\right )^{3} + 5 \, a \tan \left (d x + c\right )^{2} - 15 \, b \tan \left (d x + c\right )\right )}}{\sqrt {\tan \left (d x + c\right )}}}{30 \, d} \]
1/30*(15*d*sqrt((d^2*sqrt(-(a^4 - 2*a^2*b^2 + b^4)/d^4) + 2*a*b)/d^2)*log( (a*d^3*sqrt(-(a^4 - 2*a^2*b^2 + b^4)/d^4) - (a^2*b - b^3)*d)*sqrt((d^2*sqr t(-(a^4 - 2*a^2*b^2 + b^4)/d^4) + 2*a*b)/d^2) - (a^4 - b^4)*sqrt(tan(d*x + c))) - 15*d*sqrt((d^2*sqrt(-(a^4 - 2*a^2*b^2 + b^4)/d^4) + 2*a*b)/d^2)*lo g(-(a*d^3*sqrt(-(a^4 - 2*a^2*b^2 + b^4)/d^4) - (a^2*b - b^3)*d)*sqrt((d^2* sqrt(-(a^4 - 2*a^2*b^2 + b^4)/d^4) + 2*a*b)/d^2) - (a^4 - b^4)*sqrt(tan(d* x + c))) - 15*d*sqrt(-(d^2*sqrt(-(a^4 - 2*a^2*b^2 + b^4)/d^4) - 2*a*b)/d^2 )*log((a*d^3*sqrt(-(a^4 - 2*a^2*b^2 + b^4)/d^4) + (a^2*b - b^3)*d)*sqrt(-( d^2*sqrt(-(a^4 - 2*a^2*b^2 + b^4)/d^4) - 2*a*b)/d^2) - (a^4 - b^4)*sqrt(ta n(d*x + c))) + 15*d*sqrt(-(d^2*sqrt(-(a^4 - 2*a^2*b^2 + b^4)/d^4) - 2*a*b) /d^2)*log(-(a*d^3*sqrt(-(a^4 - 2*a^2*b^2 + b^4)/d^4) + (a^2*b - b^3)*d)*sq rt(-(d^2*sqrt(-(a^4 - 2*a^2*b^2 + b^4)/d^4) - 2*a*b)/d^2) - (a^4 - b^4)*sq rt(tan(d*x + c))) + 4*(3*b*tan(d*x + c)^3 + 5*a*tan(d*x + c)^2 - 15*b*tan( d*x + c))/sqrt(tan(d*x + c)))/d
\[ \int \frac {a+b \tan (c+d x)}{\cot ^{\frac {5}{2}}(c+d x)} \, dx=\int \frac {a + b \tan {\left (c + d x \right )}}{\cot ^{\frac {5}{2}}{\left (c + d x \right )}}\, dx \]
Time = 0.31 (sec) , antiderivative size = 165, normalized size of antiderivative = 0.82 \[ \int \frac {a+b \tan (c+d x)}{\cot ^{\frac {5}{2}}(c+d x)} \, dx=\frac {8 \, {\left (3 \, b + \frac {5 \, a}{\tan \left (d x + c\right )} - \frac {15 \, b}{\tan \left (d x + c\right )^{2}}\right )} \tan \left (d x + c\right )^{\frac {5}{2}} + 30 \, \sqrt {2} {\left (a - b\right )} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} + \frac {2}{\sqrt {\tan \left (d x + c\right )}}\right )}\right ) + 30 \, \sqrt {2} {\left (a - b\right )} \arctan \left (-\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} - \frac {2}{\sqrt {\tan \left (d x + c\right )}}\right )}\right ) + 15 \, \sqrt {2} {\left (a + b\right )} \log \left (\frac {\sqrt {2}}{\sqrt {\tan \left (d x + c\right )}} + \frac {1}{\tan \left (d x + c\right )} + 1\right ) - 15 \, \sqrt {2} {\left (a + b\right )} \log \left (-\frac {\sqrt {2}}{\sqrt {\tan \left (d x + c\right )}} + \frac {1}{\tan \left (d x + c\right )} + 1\right )}{60 \, d} \]
1/60*(8*(3*b + 5*a/tan(d*x + c) - 15*b/tan(d*x + c)^2)*tan(d*x + c)^(5/2) + 30*sqrt(2)*(a - b)*arctan(1/2*sqrt(2)*(sqrt(2) + 2/sqrt(tan(d*x + c)))) + 30*sqrt(2)*(a - b)*arctan(-1/2*sqrt(2)*(sqrt(2) - 2/sqrt(tan(d*x + c)))) + 15*sqrt(2)*(a + b)*log(sqrt(2)/sqrt(tan(d*x + c)) + 1/tan(d*x + c) + 1) - 15*sqrt(2)*(a + b)*log(-sqrt(2)/sqrt(tan(d*x + c)) + 1/tan(d*x + c) + 1 ))/d
\[ \int \frac {a+b \tan (c+d x)}{\cot ^{\frac {5}{2}}(c+d x)} \, dx=\int { \frac {b \tan \left (d x + c\right ) + a}{\cot \left (d x + c\right )^{\frac {5}{2}}} \,d x } \]
Timed out. \[ \int \frac {a+b \tan (c+d x)}{\cot ^{\frac {5}{2}}(c+d x)} \, dx=\int \frac {a+b\,\mathrm {tan}\left (c+d\,x\right )}{{\mathrm {cot}\left (c+d\,x\right )}^{5/2}} \,d x \]